50x^2-110x+20=0

Solution for 50x^2-110x+20=0 equation:

50x^2-110x+20=0

a = 50; b = -110; c = +20;
Δ = b2-4ac
Δ = -1102-4·50·20
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-90}{2*50}=\frac{20}{100}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+90}{2*50}=\frac{200}{100}
=2
$